JAVA 大数 A+B问题

这是一个简单的数学问题,给定两个整数A和B,任务是计算A+B的总和。输入包含多个测试用例,每个用例由两个正整数组成,需要注意的是,这些整数可能非常大,不能使用32位整数进行处理。输出应为每个测试用例的A+B=Sum形式的等式。

A + B Problem II

 

I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B. 

Input

The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000. 

Output

For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line is the an equation "A + B = Sum", Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases. 

Sample Input

2
1 2
112233445566778899 998877665544332211

Sample Output

Case 1:
1 + 2 = 3

Case 2:
112233445566778899 + 998877665544332211 = 1111111111111111110

代码:

import java.io.BufferedInputStream;
import java.math.BigInteger;
import java.util.Scanner;

public class Main {

	public static void main(String[] args) {
		// TODO 自动生成的方法存根
		Scanner str = new Scanner(System.in);
		int T;
		T=str.nextInt();
		int i=1;
		

		for(i=1;i<=T;i++)
		{
			BigInteger a=str.nextBigInteger();
			BigInteger b=str.nextBigInteger();
			System.out.println("Case "+i+":");
			System.out.println(a+" + "+b+" = "+a.add(b));
			if(i<T)
			{
			System.out.println("");
			}
			
		}

	}

}

 

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