二进制中1的个数

class Solution {
public:
	 int  NumberOf1(int n) {
		 int num = 1;
         int count = 0;
         for(int i = 0; i < 32; i++){
             if((n & num) % 2 != 0)
                 count++;
             n = n >> 1;
         }
         return count;
	 }
};