最大9位全数字组合
本文探讨了如何通过一个整数与其连续倍数的连接来形成一个包含所有1到9数字且不重复的9位数，并寻找这样的组合中最大的一个。
Take the number 192 and multiply it by each of 1, 2, and 3:
192 × 1 = 192
192 × 2 = 384
192 × 3 = 576
By concatenating each product we get the 1 to 9 pandigital, 192384576. We will call 192384576 the concatenated product of 192 and (1,2,3)
The same can be achieved by starting with 9 and multiplying by 1, 2, 3, 4, and 5, giving the pandigital, 918273645, which is the concatenated product of 9 and (1,2,3,4,5).
What is the largest 1 to 9 pandigital 9-digit number that can be formed as the concatenated product of an integer with (1,2, ... , n) where n > 1?
求最大的9位pandigital数，附合条件：
由一个数X（1，2，。。，n），n为这个数的位数。
它们的乘积组成一个9位pandigital数
192 × 1 = 192
192 × 2 = 384
192 × 3 = 576
By concatenating each product we get the 1 to 9 pandigital, 192384576. We will call 192384576 the concatenated product of 192 and (1,2,3)
The same can be achieved by starting with 9 and multiplying by 1, 2, 3, 4, and 5, giving the pandigital, 918273645, which is the concatenated product of 9 and (1,2,3,4,5).
What is the largest 1 to 9 pandigital 9-digit number that can be formed as the concatenated product of an integer with (1,2, ... , n) where n > 1?
求最大的9位pandigital数，附合条件：
由一个数X（1，2，。。，n），n为这个数的位数。
它们的乘积组成一个9位pandigital数
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970
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