复杂json遍历取值

最新推荐文章于 2022-11-03 10:49:24 发布

原创最新推荐文章于 2022-11-03 10:49:24 发布 · 661 阅读

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//转成list对其遍历
List<String> stringList = JSONObject.parseArray(obdsns, String.class);
System.out.println("设备编号取值第一个"+stringList.get(1).toString());
if(stringList.size()>0){
    for(int i=0;i<stringList.size();i++){
       
        for (Map.Entry<String, Object> entry : JSON.parseObject(stringList.get(i).toString()).entrySet()) {
            tDeviceReplaceOrderDetails.setOldObdSN(String.valueOf(entry.getValue()));
        }
        tDeviceReplaceOrderDetails.setCreatedTime(date);
        tDeviceReplaceOrderDetails.settOrgId(td.gettOrgId());
        iTDevicereplaceOrderService.insertDevice(tDeviceReplaceOrderDetails);
    }

}