pku 1008 解题报告

题目：Maya Calendar

题意：对两个日历进行转换。

代码：

#include <stdio.h>
#include <string.h>

  char month1[19][10]
  ={"pop","no","zip","zotz","tzec","xul","yoxkin","mol","chen","yax","zac",
"ceh","mac","kankin","muan","pax","koyab","cumhu","uayet"};
  char month2[20][10]
  ={"imix","ik","akbal","kan","chicchan","cimi","manik","lamat","muluk",
  "ok","chuen","eb","ben","ix","mem","cib","caban","eznab","canac","ahau"};
int main()
{
 int n;
 
 int day, year, dates,m;
    char month[10];
 scanf("%d",&n);
 printf("%d/n",n);
 while(n--)
 {
  
  scanf("%d. %s %d", &day, month, &year);
  for(m = 0; m < 19; m++) 
               if (strcmp(month1[m], month)==0) break;
       dates = year * 365 + m * 20 + day;
   /* year=dates/260;
    monthone=(dates-260*year-1)/20;
    day=dates-year*260-monthone*20;
    printf("%d %s %d/n", day, month2[monthone],year);*/
   printf("%d %s %d/n", 1 + dates % 13, month2[dates % 20], dates / 260); //从书上学到的 解决了很多问题。嘿嘿自己写

//的时候出现的错误和小错误很多。

 }

 return 0;
}