POJ 3096 Surprising Strings

最新推荐文章于 2017-07-24 18:03:29 发布

原创最新推荐文章于 2017-07-24 18:03:29 发布 · 240 阅读

0 ·

CC 4.0 BY-SA版权

文章标签：

#poj

poj 同时被 2 个专栏收录

53 篇文章

订阅专栏

STL

2 篇文章

订阅专栏

本文介绍了一个关于字符串的独特挑战——SurprisingStrings问题。该问题要求判断一个字符串是否对于所有可能的距离D都是唯一的，并提供了一个算法解决方案，使用C++实现。

Surprising Strings

Time Limit: 1000MS		Memory Limit: 65536K
Total Submissions: 6884		Accepted: 4457

Description

The D-pairs of a string of letters are the ordered pairs of letters that are distance D from each other. A string is D-unique if all of its D-pairs are different. A string is surprising if it is D-unique for every possible distance D.

Consider the string ZGBG. Its 0-pairs are ZG, GB, and BG. Since these three pairs are all different, ZGBG is 0-unique. Similarly, the 1-pairs of ZGBG are ZB and GG, and since these two pairs are different, ZGBG is 1-unique. Finally, the only 2-pair of ZGBG is ZG, so ZGBG is 2-unique. Thus ZGBG is surprising. (Note that the fact that ZG is both a 0-pair and a 2-pair of ZGBG is irrelevant, because 0 and 2 are different distances.)

Acknowledgement: This problem is inspired by the "Puzzling Adventures" column in the December 2003 issue of Scientific American.

Input

The input consists of one or more nonempty strings of at most 79 uppercase letters, each string on a line by itself, followed by a line containing only an asterisk that signals the end of the input.

Output

For each string of letters, output whether or not it is surprising using the exact output format shown below.

Sample Input

ZGBG
X
EE
AAB
AABA
AABB
BCBABCC
*

Sample Output

ZGBG is surprising.
X is surprising.
EE is surprising.
AAB is surprising.
AABA is surprising.
AABB is NOT surprising.
BCBABCC is NOT surprising.

Source

Mid-Central USA 2006

题意：给出一个一个字符串，找距离为Ｄ的两个字母组成一个字符串，看有没有重复的

比如　ZGBG

当　D=0　时，有ZG , GB , BG　都不相同

当　D=1　时，有ZB , GG 　也不相同

当　D=2　时，有ZG 只有一个不想同

所以是　Surprising Strings

分析：暴力找，set

烂代码

#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <algorithm>
#include <set>
#include <string>
#include <iostream>
using namespace std;
int main()
{
    char s[100];
    int n,m,i,j,l;
    while(~scanf("%s",s))
    {
        if(strcmp(s,"*")==0)
        {
            break;
        }
        l=strlen(s);
        if(l<=2)
        {
            printf("%s is surprising.\n",s);
            continue;
        }
        set<string>q;
        set<string>::iterator it;
        int flag=0;
        for(i=1;i<=l-1;i++)
        {
            q.clear();
            string x;
           // printf("%d\n",i);
            for(j=0;j<l;j++)
            {
                x.clear();
                if(j+i<l)
                {
                    x+=s[j];
                    x+=s[j+i];
                    x+='\0';
                }
                //cout<<x<<endl;
                if(x.size()!=0)
                {
                    if(q.find(x)==q.end())
                    {
                        q.insert(x);
                    }
                    else
                    {
                        flag=1;
                        break;
                    }
                }

//                for(it=q.begin();it!=q.end();it++)
//                {
//                    cout<<*it<<endl;
//                }
            }
            if(flag)
            {
                break;
            }
        }
        if(flag)
        {
            printf("%s is NOT surprising.\n",s);
        }
        else
        {
            printf("%s is surprising.\n",s);
        }

    }

    return 0;
}