[C++学习笔记] - char[]与char*的理解

https://www.cnblogs.com/Fflyqaq/p/12002635.html

示例

int main()
{
	char s1[] = "hi";
	const char* s2 = "hi";

	cout << "*s1: " << static_cast<void*>(&s1) << endl;
	cout << "s1: " << static_cast<const void*>(s1) << endl;
	cout << "*s2: " << static_cast<void*>(&s2) << endl;
	cout << "s2: " << static_cast<const void*>(s2) << endl;

	s1[2] = 'o';
	//s1 = "1111"; // error

	//s2[1] = 'o'; // error
	s2 = "1111";
	cout << "=========================================" << endl;

	cout << "*s1: " << static_cast<void*>(&s1) << endl;
	cout << "s1: " << static_cast<const void*>(s1) << endl;
	cout << "*s2: " << static_cast<void*>(&s2) << endl;
	cout << "s2: " << static_cast<const void*>(s2) << endl;

	char a1[] = "abc";
	char a2[] = "abc";
	const char* a3 = "abc";
	const char* a4 = "abc";
	cout << "=========================================" << endl;
	cout << "*a1: " << static_cast<void*>(&a1) << endl;
	cout << "a1: " << static_cast<const void*>(a1) << endl;
	cout << "*a2: " << static_cast<void*>(&a2) << endl;
	cout << "a2: " << static_cast<const void*>(a2) << endl;
	cout << "*a3: " << static_cast<void*>(&a3) << endl;
	cout << "a3: " << static_cast<const void*>(a3) << endl;
	cout << "*a4: " << static_cast<void*>(&a4) << endl;
	cout << "a4: " << static_cast<const void*>(a4) << endl;
}

1. 对象s1，s2的内存地址都没改变。
2. s2指向的内容的地址变了
3. s1指向的内容改变了。
4. s1无法指向新的地址内容，可以修改当前。
5. s2无法修改当前指向内容，可以重新指向。
6. char[]指向的内容是拷贝，即使多个对象内容相同，如abc，但他们指向内容的地址不同。
7. char*指向地址，如果多个对象内容相同，如abc，他们指向的内容地相同。