题目来源:http://218.194.91.48/acmhome/problemdetail.do?&method=showdetail&id=1455
描述
Traditionally after the Local Contest, judges and contestants go to their favourite restaurant, Alfredos Pizza Restaurant. The contestants are really hungry after trying hard for five hours. To get their pizza as quickly as possible, they just decided to order one big pizza for all instead of several small ones. They wonder whether it is possible to put the big rectangular pizza on the surface of the round table such that it does not overhang the border of the table. Write a program that helps them!
输入
The input file contains several test cases. Each test case starts with an integer number r, the radius of the surface of the round table the contestants are sitting at. Input is terminated by r=0. Otherwise, 1 ≤ r ≤ 1000. Then follow 2 integer numbers w and l specifying the width and the length of the pizza, 1 ≤ w ≤ l ≤ 1000.
输出
Output for each test case whether the ordered pizza will fit on the table or not. Adhere to the format shown in the sample output. A pizza which just touches the border of the table without intersecting it is considered fitting on the table, see example 3 for clarification.
样例输入
38 40 60
35 20 70
50 60 80
0
样例输出
Pizza 1 fits on the table.
Pizza 2 does not fit on the table.
Pizza 3 fits on the table.
//此题完全为一水题,问你长方形能不能放进圆里..
#include<cstdio>
int main(){
int a,b,c,id=1;
while( scanf("%d",&a) && a){
scanf("%d%d",&b,&c);
a=a*2;
if(a*a>=b*b+c*c) printf("Pizza %d fits on the table.\n",id++);
else printf("Pizza %d does not fit on the table.\n",id++);
}return 0;
}
本文探讨了一种算法,用于解决在圆形桌面上放置矩形披萨的问题。通过输入圆形桌面的半径和披萨的尺寸,算法判断披萨是否能完整地放在桌面上,不超出边界。本文详细解释了算法实现过程,包括数学原理和代码示例。
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