这道ZOJ的水题~~~让我认识了ZOJ的Segmentation Fault。坑爹~~尼玛坑爹~~输出的过程居然不能有for循环的处理程序,只能单独隔离输入,即先要保存输入。算算了,算是ZOJ的奇葩吧~~
AC program:
#include<iostream>
#include<stdio.h>
#include<string.h>
#include<algorithm>
#include<math.h>
#include<iomanip>
#include<queue>
#include<map>
using namespace std;
int main()
{
int nn[25];
int ff[25];
int mm[1000];
int n,m,c;
int cas=1;
while(cin>>n>>m>>c,n+m+c)
{
for(int i=1;i<=n;i++)
cin>>nn[i];
for(int i=1;i<=m;i++)
cin>>mm[i];//要单独输入,和下面的处理一起在for循环的话
//就会出现Segmentation Fault
//ZOJ奇葩错误
memset(ff,0,sizeof(ff));
int sum=0;
int max=-1;
int flag=0;
for(int i=1;i<=m;i++)
{
int t=mm[i];
ff[t]=1-ff[t];
if(ff[t]==1)
{
sum+=nn[t];
if(max<sum)max=sum;
if(sum>c)
{
flag=1;
break;
}
}
else
{
sum-=nn[t];
}
}
if(!flag)
{
printf("Sequence %d\n",cas++);
printf("Fuse was not blown.\n");
printf("Maximal power consumption was %d amperes.\n",max);
}
else
{
printf("Sequence %d\n",cas++);
printf("Fuse was blown.\n");
}
cout<<endl;
}
//system("pause");
return 0;}
这个博主也ORZ了:呵呵:http://blog.youkuaiyun.com/cherry_sun/article/details/6257498