codeforce Present from Lena 打印菱形

最新推荐文章于 2022-11-21 21:55:25 发布

原创最新推荐文章于 2022-11-21 21:55:25 发布 · 1.7k 阅读

0 ·

CC 4.0 BY-SA版权

Algorithm算法专栏收录该内容

568 篇文章

订阅专栏

为庆祝Vasya的生日，Lena决定送给他一块带有特定图案的手帕作为礼物。该图案由数字0到n组成，形成一个菱形，最大的数字n位于中心，向边缘逐渐减小。本篇详细介绍了如何通过编程实现这一图案。

摘要生成于 C知道，由 DeepSeek-R1 满血版支持，前往体验 >

Vasya's birthday is approaching and Lena decided to sew a patterned handkerchief to him as a present. Lena chose digits from 0 to n as the pattern. The digits will form a rhombus. The largest digit n should be located in the centre. The digits should decrease as they approach the edges. For example, for n = 5 the handkerchief pattern should look like that:

          0
        0 1 0
      0 1 2 1 0
    0 1 2 3 2 1 0
  0 1 2 3 4 3 2 1 0
0 1 2 3 4 5 4 3 2 1 0
  0 1 2 3 4 3 2 1 0
    0 1 2 3 2 1 0
      0 1 2 1 0
        0 1 0
          0

Your task is to determine the way the handkerchief will look like by the given n.

Input

The first line contains the single integer n (2 ≤ n ≤ 9).

Output

Print a picture for the given n. You should strictly observe the number of spaces before the first digit on each line. Every two adjacent digits in the same line should be separated by exactly one space. There should be no spaces after the last digit at the end of each line.

Sample test(s)

input
2

output
    0
  0 1 0
0 1 2 1 0
  0 1 0
    0

input
3

output
      0
    0 1 0
  0 1 2 1 0
0 1 2 3 2 1 0
  0 1 2 1 0
    0 1 0
      0

细心题目，没更好的办法了，一个一个字符去打印，安排出菱形。

这里分上下菱形分别打印。

#include <iostream>
using namespace std;

void PresentfromLena()
{
	int k = 0;
	cin>>k;
	for (int i = 0; i <= k; i++)
	{
		int space = k - i;
		for (int j = 0; j < space; j++)
		{
			cout<<"  ";
		}
		for (int j = 0; j <= i; j++)
		{
			cout<<j;
			if (0 != i) cout<<' ';
		}
		for (int j = i - 1; j >= 0 ; j--)
		{
			cout<<j;
			if (j != 0) cout<<' ';
		}
		cout<<endl;//不要遗忘了换行符
	}
	for (int i = k - 1; i >= 0 ; i--)
	{
		int space = k - i;
		for (int j = 0; j < space; j++)
		{
			cout<<"  ";
		}
		for (int j = 0; j <= i; j++)
		{
			cout<<j;
			if (0 != i) cout<<' ';
		}
		for (int j = i - 1; j >= 0 ; j--)
		{
			cout<<j;
			if (j != 0) cout<<' ';
		}
		cout<<endl;
	}
}