shell脚本：自定义大小颜色的国际象棋棋盘

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原创最新推荐文章于 2026-07-13 16:03:04 发布 618 阅读 AI 写同款· GEO 优化 ›

Linux Shell编程基础---国际象棋棋盘这两天在学习一些shell编程的知识，在做到一道国际象棋的题目时，觉得有些意思，就将它写成博客。先来看看国际象棋棋盘长啥样：仔细想了会棋盘的分布规则，这个问题肯定有很多思路，我自己想到的是规则是1.将棋盘行数作为一个大循环，循环8次，每次循环根据行号的奇偶来确定格子颜色的次序；2.在单个行中，循环8次并判断列的奇偶数来确定打印颜色以上思路能够打印出最简单的棋盘，但是shell中一个空格的显示形... 阅读详情

#!/bin/bash
PS3="please choice the first color :"
select color1 in hong lv huang lan zi qianlan bai hei ;do
	[[ $REPLY =~ ^[1-8]$ ]] || { echo must 1-8;continue; }
	case $color1 in
	hong)
		echo -e the first color is "\033[1;41m    \033[0m"
		break
		;;
	lv)
		echo -e the first color is "\033[1;42m    \033[0m"
		break
		;;
	huang)
		echo -e the first color is "\033[1;43m    \033[0m"
		break
		;;
	lan)
		echo -e the first color is "\033[1;44m    \033[0m"
		break
		;;
	zi)
		echo -e the first color is "\033[1;45m    \033[0m"
		break
		;;
	qianlan)
		echo -e the first color is "\033[1;46m    \033[0m"
		break
		;;
	bai)
		echo -e the first color is "\033[1;47m    \033[0m"
		break
		;;
	hei)
		echo -e the first color is "\033[1;48m    \033[0m"
		break
		;;
	esac
done

PS3="please choice the second color :"
select color2 in hong lv huang lan zi qianlan bai hei ;do
	[[ $REPLY =~ ^[1-8]$ ]] || { echo must 1-8;continue; }
	case $color2 in
	hong)
		echo -e the first color is "\033[1;41m    \033[0m"
		break
		;;
	lv)
		echo -e the first color is "\033[1;42m    \033[0m"
		break
		;;
	huang)
		echo -e the first color is "\033[1;43m    \033[0m"
		break
		;;
	lan)
		echo -e the first color is "\033[1;44m    \033[0m"
		break
		;;
	zi)
		echo -e the first color is "\033[1;45m    \033[0m"
		break
		;;
	qianlan)
		echo -e the first color is "\033[1;46m    \033[0m"
		break
		;;
	bai)
		echo -e the first color is "\033[1;47m    \033[0m"
		break
		;;
	hei)
		echo -e the first color is "\033[1;48m    \033[0m"
		break
		;;
	esac
done

read -p "please input the number of space: " n
until [[ $n =~ ^[[:digit:]]+$ ]];do
	echo "must be a number"
	unset n
	read -p "please input the number of space: " n
done
	
hong () {
for a in `seq $n`;do
echo -e "\033[1;41m \033[0m\c"
done
}
lv () {
for b in `seq $n`;do
echo -e "\033[1;42m \033[0m\c"
done
}
huang () {
for c in `seq $n`;do
echo -e "\033[1;43m \033[0m\c"
done
}
lan () {
for d in `seq $n`;do
echo -e "\033[1;44m \033[0m\c"
done
}
zi () {
for e in `seq $n`;do
echo -e "\033[1;45m \033[0m\c"
done
}
qianlan () {
for f in `seq $n`;do
echo -e "\033[1;46m \033[0m\c"
done
}
bai () {
for g in `seq $n`;do
echo -e "\033[1;47m \033[0m\c"
done
}
hei () {
for h in `seq $n`;do
echo -e "\033[1;48m \033[0m\c"
done
}


declare -i i=1
while [ $i -le 8 ];do
        if [ $[i%2] -eq 0 ];then
                declare -i j=1
                while [ $j -le 8 ];do
                        if [ $j -eq 4 ];then
				`echo $color1`;`echo $color2`
                                echo
                                let ++j
                                continue
                        fi
                        `echo $color1`;`echo $color2`
                        let ++j
                done
                echo
        else
                declare -i k=1
                while [ $k -le 8 ];do
                        if [ $k -eq 4 ];then
                                `echo $color2`;`echo $color1`
                                echo
                                let ++k
                                continue
                        fi
                        `echo $color2`;`echo $color1`
                        let ++k
                done
                echo
        fi
let ++i
done