sql学习记录

leetcode上的blog


有下表。


+---------+------------+
| student | class      |
+---------+------------+
| A       | Math       |
| B       | English    |
| C       | Math       |
| D       | Biology    |
| E       | Math       |
| F       | Computer   |
| G       | Math       |
| H       | Math       |
| I       | Math       |
+---------+------------+

统计选课人数大于5的科目。

输出

+---------+
| class   |
+---------+
| Math    |
+---------+


解决:


第一种:

第一步:

SELECT
    class, COUNT(DISTINCT student)
FROM
    courses
GROUP BY class
;

output:

| class    | COUNT(student) |
|----------|----------------|
| Biology  | 1              |
| Computer | 1              |
| English  | 1              |
| Math     | 6              |

第二步:

SELECT
    class
FROM
    (SELECT
        class, COUNT(DISTINCT student) AS num
    FROM
        courses
    GROUP BY class) AS temp_table
WHERE
    num >= 5
;
第二种:

Mysql


SELECT
    class
FROM
    courses
GROUP BY class
HAVING COUNT(DISTINCT student) >= 5
;






评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值