A+B Problem
Time Limit:1000MS Memory Limit:10000K
Total Submit:48745 Accepted:26325 
Description
Calculate a+b 
Input
Two integer a,b (0<=a,b<=10)
Output
Output a+b
Sample Input

1 2
Sample Output

3
Hint
Q: Where are the input and the output? 
A: Your program shall always read input from stdin (Standard Input) and write output to stdout (Standard Output). For example, you can use 'scanf' in C or 'cin' in C++ to read from stdin, and use 'printf' in C or 'cout' in C++ to write to stdout. 
You shall not output any extra data to standard output other than that required by the problem, otherwise you will get a "Wrong Answer". 
User programs are not allowed to open and read from/write to files. You will get a "Runtime Error" or a "Wrong Answer" if you try to do so. 
Here is a sample solution for problem 1000 using C++/G++: 

#include <iostream>
using namespace std;
int main()
...{
int a,b;
cin >> a >> b;
cout << a+b << endl;
return 0;
}
It's important that the return type of main() must be int when you use G++/GCC,or you may get compile error. 
Here is a sample solution for problem 1000 using C/GCC: 
#include <stdio.h>
int main()
...{
int a,b;
scanf("%d %d",&a, &b);
printf("%d ",a+b);
return 0;
}
Here is a sample solution for problem 1000 using PASCAL: 
program p1000(Input,Output);
var
a,b:Integer;
begin
Readln(a,b);
Writeln(a+b);
end.
Here is a sample solution for problem 1000 using JAVA: 
Now java compiler is jdk 1.5, next is program for 1000 
import java.io.*;
import java.util.*;
public class Main
...{
public static void main(String args[]) throws Exception
...{
Scanner cin=new Scanner(System.in);
int a=cin.nextInt(),b=cin.nextInt();
System.out.println(a+b);
}
}
Old program for jdk 1.4 
import java.io.*;
import java.util.*;
public class Main
...{
public static void main (String args[]) throws Exception
...{
BufferedReader stdin =
new BufferedReader(
new InputStreamReader(System.in));
String line = stdin.readLine();
StringTokenizer st = new StringTokenizer(line);
int a = Integer.parseInt(st.nextToken());
int b = Integer.parseInt(st.nextToken());
System.out.println(a+b);
}
}
Source
POJ

my solution:
Source
Problem Id:1000 User Id:keepRunning
Memory:92K Time:0MS
Language:C++ Result:Accepted
Source 
#include<iostream>
using namespace std;

int main( void ) ...{
int a;
int b;
cin >> a >> b;
if( a >= 0 && b <= 10 )
cout << a + b;
else cout << "error";
return 0;
}


784

被折叠的 条评论
为什么被折叠?



