1036. Boys vs Girls (25)

最新推荐文章于 2021-02-24 15:09:01 发布

原创最新推荐文章于 2021-02-24 15:09:01 发布 · 265 阅读

1 ·

CC 4.0 BY-SA版权

pat-advanced 专栏收录该内容

115 篇文章

订阅专栏

本程序旨在从学生数据中找出男性学生的最低分数与女性学生的最高分数，并计算两者之间的差距。输入包括学生的姓名、性别、学号及分数，输出则包含最高分女性学生与最低分男性学生的信息，以及他们的分数差值。若缺少任一性别学生，则相应输出'Absent'。

摘要生成于 C知道，由 DeepSeek-R1 满血版支持，前往体验 >

This time you are asked to tell the difference between the lowest grade of all the male students and the highest grade of all the female students.

Input Specification:

Each input file contains one test case. Each case contains a positive integer N, followed by N lines of student information. Each line contains a student's name, gender, ID and grade, separated by a space, where name and ID are strings of no more than 10 characters with no space, gender is either F (female) or M (male), and grade is an integer between 0 and 100. It is guaranteed that all the grades are distinct.

Output Specification:

For each test case, output in 3 lines. The first line gives the name and ID of the female student with the highest grade, and the second line gives that of the male student with the lowest grade. The third line gives the difference grade_F-grade_M. If one such kind of student is missing, output "Absent" in the corresponding line, and output "NA" in the third line instead.

Sample Input 1:

3
Joe M Math990112 89
Mike M CS991301 100
Mary F EE990830 95

Sample Output 1:

Mary EE990830
Joe Math990112
6

Sample Input 2:

1
Jean M AA980920 60

Sample Output 2:

Absent
Jean AA980920
NA

找出男生中的最低分和女生中的最高分，在输入的时候更新最低分的男生的信息和最高分女生的信息即可。如果男生和女生都有，输出最高分的女生和最低分的男生的姓名与学号，并且输出他们之间的分差；如果缺少男生或女生，缺少的那个输出“Absent”，其他的和前面的一样，最后输出“NA”代表没有分差这个概念。

代码：

#include <iostream>
#include <cstring>
#include <vector>
#include <cstdlib>
#include <cstdio>
using namespace std;

#define INF 1<<30

int main()
{
	int n;
	cin>>n;
	string mname="",mid,fname="",fid;
	int mgrade=INF,fgrade=0;
	for(int i=0;i<n;i++)
	{
		string name,id;
		char sex;
		int grade;
		cin>>name>>sex>>id>>grade;
		if(sex=='M')
		{
			if(grade<mgrade)
			{
				mname=name;
				mid=id;
				mgrade=grade;
			}
		}
		else
		{
			if(grade>fgrade)
			{
				fname=name;
				fid=id;
				fgrade=grade;
			}
		}
	}
	if(mname!=""&&fname!="")
	{
		cout<<fname<<" "<<fid<<endl;
		cout<<mname<<" "<<mid<<endl;
		cout<<fgrade-mgrade<<endl;
	}
	else 
	{
		if(fname=="") cout<<"Absent"<<endl;
		else cout<<fname<<" "<<fid<<endl;
		if(mname=="") cout<<"Absent"<<endl;
		else cout<<mname<<" "<<mid<<endl;
		cout<<"NA"<<endl;
	}
}