摘要:
本文使用两个例子展示了如何使用Hibernate来持久化java 5 的枚举类型(Enum )
Java 5 Enums Persistence with Hibernate
标题:
【原创翻译】使用Hibernate持久化java 5 的枚举类型【AppFuse 2.0 文档-11】
作者:
Added by eboz, last edited by eboz on Jun 05, 2007 17:43
翻译者: 陈海青(josonchen)
日期:2007.11.22
摘要:
本文使用两个例子展示了如何使用Hibernate来持久化java 5 的枚举类型(Enum )
关键字:
Appfuse 2.0 , java 5,enum,
annotations , Hibernate,
英文版网址
:
http://appfuse.org/display/APF/Java+5+Enums+Persistence+with+Hibernate
中文版
-------
关于本教程
如果你需要使用
JPA
的注释(
annotation
)将
Java 5
的枚举类型(
Enum
)映射到
Hibernate
,那么本文就是你需要的
.
目录
书写JPA 注释(annotations)
首先,使用一个来自
AppFuse
持久化教程的经典
POJO
的例子来展示如何使用注释
(annotation).
package org.appfuse.tutorial.model;
@Entity
@Table(name="t_person")
public class Person extends BaseObject {
// Enumerations ---------------------------
public enum Sex{
MALE(1),
FEMALE(2);
private int value;
Sex(int value) {
this.value = value;
}
// the identifierMethod
public int toInt() {
return value;
}
// the valueOfMethod
public static Sex fromInt(int value) {
switch(value) {
case 1: return MALE;
case 2: return FEMALE;
default:
return UNKNOW;
}
}
public String toString() {
switch(this) {
case MALE:
return "Male";
case FEMALE:
return "Female";
}
}
}
// Attributes ---------------------------
@Id
@Column(name= "person_id")
@GeneratedValue(strategy = GenerationType.AUTO)
private Long id;
@Column(name="person_firstname", length = 50, nullable = false)
private String firstName;
@Column(name="person_lastname", length = 50, nullable = false)
private String lastName;
@Column(name= "person_sex", columnDefinition="integer", nullable = true)
@Type(
type = "org.appfuse.tutorial.commons.hibernate.GenericEnumUserType",
parameters = {
@Parameter(
name = "enumClass",
value = "org.appfuse.tutorial.model.Person$Sex"),
@Parameter(
name = "identifierMethod",
value = "toInt"),
@Parameter(
name = "valueOfMethod",
value = "fromInt")
}
)
private Sex sex;
/*
* Getters and Setters ...
*/
}
把Java 5 的枚举类型(Enum)映射到Hibernate
现在,使用以下的灵活方案
(Flexible solution) –
一个可运行版本(
working version
)
来映射
Sex
属性。这里要感谢
Martin Kersten,
他的文章
Java 5 EnumUserType
提供了帮助
.
package org.appfuse.tutorial.commons.hibernate;
import java.io.Serializable;
import java.lang.reflect.Method;
import java.sql.PreparedStatement;
import java.sql.ResultSet;
import java.sql.SQLException;
import java.util.Properties;
import org.hibernate.HibernateException;
import org.hibernate.type.NullableType;
import org.hibernate.type.TypeFactory;
import org.hibernate.usertype.ParameterizedType;
import org.hibernate.usertype.UserType;
public class GenericEnumUserType implements UserType, ParameterizedType {
private static final String DEFAULT_IDENTIFIER_METHOD_NAME = "name";
private static final String DEFAULT_VALUE_OF_METHOD_NAME = "valueOf";
private Class<? extends Enum> enumClass;
private Class<?> identifierType;
private Method identifierMethod;
private Method valueOfMethod;
private NullableType type;
private int[] sqlTypes;
public void setParameterValues(Properties parameters) {
String enumClassName = parameters.getProperty("enumClass");
try {
enumClass = Class.forName(enumClassName).asSubclass(Enum.class);
} catch (ClassNotFoundException cfne) {
throw new HibernateException("Enum class not found", cfne);
}
String identifierMethodName = parameters.getProperty("identifierMethod", DEFAULT_IDENTIFIER_METHOD_NAME);
try {
identifierMethod = enumClass.getMethod(identifierMethodName, new Class[0]);
identifierType = identifierMethod.getReturnType();
} catch (Exception e) {
throw new HibernateException("Failed to obtain identifier method", e);
}
type = (NullableType) TypeFactory.basic(identifierType.getName());
if (type == null)
throw new HibernateException("Unsupported identifier type " + identifierType.getName());
sqlTypes = new int[] { type.sqlType() };
String valueOfMethodName = parameters.getProperty("valueOfMethod", DEFAULT_VALUE_OF_METHOD_NAME);
try {
valueOfMethod = enumClass.getMethod(valueOfMethodName, new Class[] { identifierType });
} catch (Exception e) {
throw new HibernateException("Failed to obtain valueOf method", e);
}
}
public Class returnedClass() {
return enumClass;
}
public Object nullSafeGet(ResultSet rs, String[] names, Object owner) throws HibernateException, SQLException {
Object identifier = type.get(rs, names[0]);
if (identifier == null) {
return null;
}
try {
return valueOfMethod.invoke(enumClass, new Object[] { identifier });
} catch (Exception e) {
throw new HibernateException("Exception + valueOfMethod.getName() + "' of " +while invoking valueOf method '"
"enumeration class '" + enumClass + "'", e);
}
}
public void nullSafeSet(PreparedStatement st, Object value, int index) throws HibernateException, SQLException {
try {
if (value == null) {
st.setNull(index, type.sqlType());
} else {
Object identifier = identifierMethod.invoke(value, new Object[0]);
type.set(st, identifier, index);
}
} catch (Exception e) {
throw new HibernateException("Exception + identifierMethod.getName() + "' of " +while invoking identifierMethod '"
"enumeration class '" + enumClass + "'", e);
}
}
public int[] sqlTypes() {
return sqlTypes;
}
public Object assemble(Serializable cached, Object owner) throws HibernateException {
return cached;
}
public Object deepCopy(Object value) throws HibernateException {
return value;
}
public Serializable disassemble(Object value) throws HibernateException {
return (Serializable) value;
}
public boolean equals(Object x, Object y) throws HibernateException {
return x == y;
}
public int hashCode(Object x) throws HibernateException {
return x.hashCode();
}
public boolean isMutable() {
return false;
}
public Object replace(Object original, Object target, Object owner) throws HibernateException {
return original;
}
}