一个小孩的自我踌躇

There is a famous railway station in PopPush City. Country there is incredibly hilly. The station was built in last century. Unfortunately, funds were extremely limited that time. It was possible to

N个点M条边的无向连通图，每条边有一个权值，求该图的最小生成树。 Input 第1行：2个数N,M中间用空格分隔，N为点的数量，M为边的数量。（2 <= N <= 1000, 1 <= M <= 50000) 第2 - M + 1行：每行3个数S E W，分别表示M条边的2个顶点及权值。(1 <= S, E <= N，1 <= W <= 10000) Output 输出最小生成树的所有边

#include <iostream> #include <cstdio> #include <algorithm> #include <string> using namespace std; const int maxcol=60; const int maxn=100+5; string filename[maxn]; void print(string x,int len,char str)

#include <queue> #include <cstdio> #include <iostream> #include <algorithm> #include <set> #define ll long long using namespace std; int a[3]={2,3,5}; int main() { priority_queue<ll ,vector<ll>, g

#include <iostream> #include <cstdio> #include <algorithm> #include <vector> #include <queue> #include <map> using namespace std; int main() { // freopen("input.txt","r",stdin); int cmt; int c

#include <iostream> #include <cstdio> #include <set> #include <vector> #include <map> #include <stack> #include <algorithm> using namespace std; #define ALL(x) x.begin(),x.end() #define INS(x) insert

题目大意：将n节木棒接成m个长度相等的木条，要求木条的长度尽可能的短#include <bits/stdc++.h>using namespace std; #define LL long long #define LD long double #define SC(t,x) static_cast<t>(x) #define AR(t) vector < t > #define PII pair