Jimmy_King

1.1三角形1. 半周长 P=(a+b+c)/22. 面积 S=aHa/2=absin(C)/2=sqrt(P(P-a)(P-b)(P-c))3. 中线 Ma=sqrt(2(b^2+c^2)-a^2)/2=sqrt(b^2+c^2+2bccos(A))/24. 角平分线 Ta=sqrt(bc((b+c)^2-a^2))/(b+c)=2bccos(A/2)/(b+c)5. 高线 Ha=bs

Chess

小C的倍数问题Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Problem Description根据小学数学的知识，我们知道一个正整数x是3的倍数的条件是x每一位加起来的和是3的倍数。反之，如果一个数每一位加起来是3的倍数，则这个数肯定是3的倍数。现在给定进制P

GYM-101608-M

CF-GYM-101498-F

CF-101466-CLately the communication between planets has been an important issue, which is why the Earth has made many efforts to be connected to every other planet in the universe. The Universal N

CF-gym-334-AGerald has n younger brothers and their number happens to be even. One day he bought n2 candy bags. One bag has one candy, one bag has two candies, one bag has three candies and so on. I

Auxiliary Project

求递推式，构造一个矩阵，根据矩阵乘法规则

位运算

判断闰年，判断星期几

组合数取模就是求 CnmmodpCmnmodpC^n_m\mod p 的值，当然根据n,m,pn,m,pn,m,p的取值范围不同，采取的方法也不一样。 ppp比较大就只能一个一个算如LL C_one_by_one(LL n, LL m)//组合数一个一个算但是不是很大的要预先处理好阶乘 数很大需要逆元typedef long long LL;LL MOD;LL fac[...

卢卡斯定理 主席树 Sunday AC自动机 链式前向星#include<string.h>#define MAX 10000struct node{ int to,nex,wei;}edge[MAX*2+5];int head[MAX+5],cnt;void add(int u,int v,int w)//添加一个单向边u->v 权为w {...

G. PairsThe pair in the land of 1000000007 is the pair of numbers a and b with the following relation: a × b = 1 (mod 1000000007). It is believed to be the sign of divine. Your task is to increase t...