Determine whether an integer is a palindrome. Do this without extra space.
Some hints:
class Solution(object):Could negative integers be palindromes? (ie, -1)
If you are thinking of converting the integer to string, note the restriction of using extra space.
You could also try reversing an integer. However, if you have solved the problem "Reverse Integer", you know that the reversed integer might overflow. How would you handle such case?
There is a more generic way of solving this problem.
选择分离数字的方法,当然要用到大量除10和取余数的计算。
def isPalindrome(self, x):
"""
:type x: int
:rtype: bool
"""
o=x
ret=0
flag=1
if x<0:
return False
while(x!=0):
ret=ret*10+x%10
x=x/10
return ret==o
整数回文判断
本文介绍了一种不使用额外空间判断整数是否为回文数的方法。通过不断将整数除以10并取余数的方式逆序整数,最后比较逆序后的整数与原整数是否相等。
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