codeforce_844A

本文介绍了一个编程挑战,目标是最少次数地改变字符串中的字符,以达到包含至少k个不同字母的要求。文章提供了示例输入输出,并解释了解决方案思路。

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Diversity
Time Limit: 1000msMemory Limit: 262144KB This problem will be judged on CodeForces. Original ID: 844A
64-bit integer IO format: %I64d Java class name: (Any)
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Calculate the minimum number of characters you need to change in the string s, so that it contains at least k different letters, or print that it is impossible.

String s consists only of lowercase Latin letters, and it is allowed to change characters only to lowercase Latin letters too.

Input
First line of input contains string s, consisting only of lowercase Latin letters (1 ≤ |s| ≤ 1000, |s| denotes the length of s).

Second line of input contains integer k (1 ≤ k ≤ 26).

Output
Print single line with a minimum number of necessary changes, or the word «impossible» (without quotes) if it is impossible.

Sample Input
Input
yandex
6
Output
0
Input
yahoo
5
Output
1
Input
google
7
Output
impossible
Hint
In the first test case string contains 6 different letters, so we don’t need to change anything.

In the second test case string contains 4 different letters: {‘a’, ‘h’, ‘o’, ‘y’}. To get 5 different letters it is necessary to change one occurrence of ‘o’ to some letter, which doesn’t occur in the string, for example, {‘b’}.

In the third test case, it is impossible to make 7 different letters because the length of the string is 6.

Source
AIM Tech Round 4 (Div. 2)

mean 看案例就能看懂把

#include<bits/stdc++.h>
using namespace std;
const int mm=1e9;
int main()
{
    char s[1111];
    int n,i,j;
    while(cin>>s>>n)
    {
        int len=strlen(s);
        set<char>  st;
        int cnt=0;
        for(i=0;i<len;i++)
        {
            if(st.find(s[i])==st.end())
                st.insert(s[i]);
            else cnt++;
        }
        int ans=st.size()+cnt;
        if(ans>=26)
            ans=26;
        if(ans<n)
            puts("impossible");
        else
        {
            if(n>st.size())
            cout<<n-st.size()<<endl;
            else puts("0");
        }

    }
}
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