Given an unsorted array of integers, find the length of the longest consecutive elements sequence.
For example,
Given [100, 4, 200, 1, 3, 2]
,
The longest consecutive elements sequence is [1, 2, 3, 4]
. Return its length: 4
.
Your algorithm should run in O(n) complexity.
class Solution {
public:
int longestConsecutive(vector<int> &num) {
// Start typing your C/C++ solution below
// DO NOT write int main() function
unordered_map<int,int> hashMap;
for(int i=0;i<num.size();i++)
{
hashMap[num.at(i)]=i;
}
int maxLength=1;
vector<int> visited(num.size(),0);
for(int i=0;i<num.size();i++)
{
if(visited[i]==1) continue;
visited[i]=1;
//find whether num[i]+1 is in the array
int number=num.at(i);
int length=1;
while(hashMap.find(number+1) != hashMap.end())
{
number++;
visited[hashMap[number]]=1;
length++;
}
number=num.at(i);
while(hashMap.find(number-1) != hashMap.end())
{
number--;
visited[hashMap[number]]=1;
length++;
}
if(length > maxLength) maxLength=length;
}
return maxLength;
}
};