(1)找出重复的信息
SELECT comname FROM (SELECT comname,COUNT(comname) AS times FROM test_bf.`test_table`
GROUP BY comname) b
WHERE b.times > 1;
(2)删除重复的信息
delete from test_bf.`test_table` where comname in
(SELECT comname FROM (SELECT comname,COUNT(comname) AS times FROM test_bf.`test_table`
GROUP BY comname) b
WHERE b.times > 1;)
SELECT comname,COUNT(comname) AS times FROM test_bf.`test_table` GROUP BY comname) b