poj 1833 排列

题意：求接下来的第k个排列

思路：next_permutation，书上有实现方法

#include <cstdio>
#include <algorithm>
using namespace std;

int t, n, q, a[1040];
int main()
{
	scanf("%d", &t);
	while (t --)
	{
		scanf("%d%d", &n, &q);
		for (int i = 0; i < n; ++ i) scanf("%d", &a[i]);
		while (q --) next_permutation(a, a+n);
		for (int i = 0; i < n-1; ++ i) printf("%d ", a[i]);
		printf("%d\n", a[n-1]);
	}
}