这道题有个点,即使用空间来对树进行分层,这个点对于不完全二叉树还是很常见的技巧
/**
* Definition for binary tree with next pointer.
* public class TreeLinkNode {
* int val;
* TreeLinkNode left, right, next;
* TreeLinkNode(int x) { val = x; }
* }
*/
public class Solution {
public void connect(TreeLinkNode root) {
if(root == null){
return;
}
LinkedList<TreeLinkNode> queue = new LinkedList<TreeLinkNode>();
LinkedList<TreeLinkNode> childQueue = new LinkedList<TreeLinkNode>();
queue.add(root);
TreeLinkNode preNode = null;
while (!queue.isEmpty()){
TreeLinkNode node = queue.remove();
if(preNode != null){
preNode.next=node;
}
preNode = node;
if(node.left != null){
childQueue.add(node.left);
}
if(node.right!=null){
childQueue.add(node.right);
}
if(queue.isEmpty() && !childQueue.isEmpty()){
queue.addAll(childQueue);
childQueue.clear();
preNode=null;
}
}
}
}