grep awk

grep -ai " cy" 200909* | awk '{print $1,$5,$15}'

cat access.log.20091013 | awk '{print substr($3,1,2)}'| sort | uniq -c

cat ua.txt ub.txt |sort|uniq -c

awk '{if(substr($3,7,4)=="0028") cp[substr($4,17,6)]++}END{for(i in cp)print i,cp[i]}' 20091209*