Number of Digit One

Given an integer n, count the total number of digit 1 appearing in all non-negative integers less than or equal to n.

For example:
Given n = 13,
Return 6, because digit 1 occurred in the following numbers: 1, 10, 11, 12, 13.

 

public class Solution {
    public int countDigitOne(int n) {
        long res = 0;
        int left = n;
        int right = 0;
        int base = 1;
        while (left > 0) {
        	int cur = left % 10;
        	left = left / 10;
        	right = n % base;
        	if (cur == 1) {
        		res += left * base;
        		res += right + 1;
        	} else if (cur == 0) {
        		res += left * base;
        	} else {
        		res += (left+1) * base;
        	}
        	right = cur * base + right;
        	base = base * 10;
        }
        return (int) res;
    }
}

 

评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值