Clone an undirected graph. Each node in the graph contains a label and a list of its neighbors.
OJ's undirected graph serialization:
Nodes are labeled uniquely.
We use# as a separator for each node, and , as a separator for node label and each neighbor of the node.
As an example, consider the serialized graph {0,1,2#1,2#2,2}.
The graph has a total of three nodes, and therefore contains three parts as separated by #.
- First node is labeled as
0. Connect node0to both nodes1and2. - Second node is labeled as
1. Connect node1to node2. - Third node is labeled as
2. Connect node2to node2(itself), thus forming a self-cycle.
Visually, the graph looks like the following:
1
/ \
/ \
0 --- 2
/ \
\_/
/**
* Definition for undirected graph.
* class UndirectedGraphNode {
* int label;
* List<UndirectedGraphNode> neighbors;
* UndirectedGraphNode(int x) { label = x; neighbors = new ArrayList<UndirectedGraphNode>(); }
* };
*/
public class Solution {
public UndirectedGraphNode cloneGraph(UndirectedGraphNode node) {
if (node == null) {
return null;
}
Queue<UndirectedGraphNode> queue = new LinkedList<>();
HashMap<UndirectedGraphNode,UndirectedGraphNode> hashMap = new HashMap<>();
UndirectedGraphNode head = new UndirectedGraphNode(node.label);
hashMap.put(node, head);
queue.add(node);
while (!queue.isEmpty()) {
UndirectedGraphNode poll = queue.poll();
for (UndirectedGraphNode uh : poll.neighbors) {
if (!hashMap.containsKey(uh)) {
queue.add(uh);
UndirectedGraphNode tmp = new UndirectedGraphNode(uh.label);
hashMap.put(uh, tmp);
}
hashMap.get(poll).neighbors.add(hashMap.get(uh));
}
}
return head;
}
}
533

被折叠的 条评论
为什么被折叠?



