Given a binary tree, flatten it to a linked list in-place.
For example,
Given
1
/ \
2 5
/ \ \
3 4 6
The flattened tree should look like:
1
\
2
\
3
\
4
\
5
\
6
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
public class Solution {
public void flatten(TreeNode root) {
LinkedList<TreeNode> linkedList = new LinkedList<TreeNode>();
TreeNode p = root;
while (p != null || !linkedList.isEmpty()) {
if (p.right != null) {
linkedList.addFirst(p.right);
}
if (p.left != null) {
p.right = p.left;
p.left = null;
} else if (!linkedList.isEmpty()) {
p.right = linkedList.poll();
}
p = p.right;
}
}
}
本文详细介绍了如何通过迭代方法将给定的二叉树结构平铺成链表形式,包括关键步骤、代码实现以及转换后的链表结构展示。
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