Follow up for "Unique Paths":
Now consider if some obstacles are added to the grids. How many unique paths would there be?
An obstacle and empty space is marked as 1 and 0 respectively in the grid.
For example,
There is one obstacle in the middle of a 3x3 grid as illustrated below.
[ [0,0,0], [0,1,0], [0,0,0] ]
The total number of unique paths is 2.
Note: m and n will be at most 100.
public class Solution {
public int uniquePathsWithObstacles(int[][] obstacleGrid) {
int m = obstacleGrid.length;
int n = obstacleGrid[0].length;
if (m <= 0 || n <= 0) {
return 0;
}
if(obstacleGrid[0][0] == 1 || obstacleGrid[m-1][n-1] == 1)
return 0;
int[][] res = new int[m][n];
res[0][0] = 1;
for (int i = 1; i < m; i++) {
if (obstacleGrid[i][0] == 1) {
res[i][0] = 0;
} else {
res[i][0] = res[i-1][0];
}
}
for (int i = 1; i < n; i++) {
if (obstacleGrid[0][i] == 1) {
res[0][i] = 0;
} else {
res[0][i] = res[0][i-1];
}
}
for (int i = 1; i < m; i++) {
for (int j = 1; j < n; j++) {
if (obstacleGrid[i][j] == 1) {
res[i][j] = 0;
} else {
res[i][j] = res[i-1][j] + res[i][j-1];
}
}
}
return res[m-1][n-1];
}
}
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