Given a list, rotate the list to the right by k places, where k is non-negative.
For example:
Given 1->2->3->4->5->NULL and k = 2,
return 4->5->1->2->3->NULL.
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int x) { val = x; }
* }
*/
public class Solution {
public ListNode rotateRight(ListNode head, int k) {
if (head == null || k == 0) {
return head;
}
ListNode p = head;
int len = 1;
while (p.next != null) {
len++;
p = p.next;
}
p.next = head;
k = k % len;
for (int i = 0; i < len - k; i++) {
p = p.next;
}
head = p.next;
p.next = null;
return head;
}
}
链表右旋算法
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