Given an array S of n integers, are there elements a, b, c in S such that a + b + c = 0? Find all unique triplets in the array which gives the sum of zero.
Note:
- Elements in a triplet (a,b,c) must be in non-descending order. (ie, a ≤ b ≤ c)
- The solution set must not contain duplicate triplets.
For example, given array S = {-1 0 1 2 -1 -4},
A solution set is:
(-1, 0, 1)
(-1, -1, 2)
public class Solution {
public List<List<Integer>> threeSum(int[] nums) {
List<List<Integer>> list = new ArrayList<List<Integer>>();
Arrays.sort(nums);
Set<ArrayList<Integer>> set = new HashSet<ArrayList<Integer>>();
for (int i = 0; i < nums.length-2; i++) {
int a = nums[i];
int start = i+1;
int end = nums.length-1;
while (start < end) {
int b = nums[start];
int c = nums[end];
if (a+b+c == 0) {
ArrayList<Integer> t = new ArrayList<Integer>();
t.add(a);
t.add(b);
t.add(c);
set.add(t);
start++;
end--;
} else if (a+b+c < 0) {
start++;
} else {
end--;
}
}
}
list.addAll(set);
return list;
}
}
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