Given n non-negative integers a1, a2, ..., an, where each represents a point at coordinate (i, ai). n vertical lines are drawn such that the two endpoints of line i is at (i, ai) and (i, 0). Find two lines, which together with x-axis forms a container, such that the container contains the most water.
Note: You may not slant the container.
public class Solution {
public int maxArea(int[] height) {
int i = 0;
int j = height.length-1;
int max = 0;
while (i < j) {
max = Math.max(Math.min(height[i], height[j])*(j-i), max);
if (height[i] < height[j]) {
i++;
} else {
j--;
}
}
return max;
}
}
本文介绍了一种利用双指针技巧解决容器最大容量问题的方法,通过遍历数组并计算不同高度间的水容量来找到最大容量。
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