Implement atoi to convert a string to an integer.
Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the possible input cases.
Notes: It is intended for this problem to be specified vaguely (ie, no given input specs). You are responsible to gather all the input requirements up front.
public class Solution {
public int myAtoi(String str) {
if (str == null || str.equals("")) {
return 0;
}
str = str.trim();
int i = 0;
boolean posi = true;
if (str.charAt(0) == '-') {
posi = false;
i++;
} else if (str.charAt(0) == '+') {
posi = true;
i++;
}
int res = 0;
int cur = 0;
for (; i < str.length() && str.charAt(i) >= '0' && str.charAt(i) <= '9'; i++) {
cur = str.charAt(i) - '0';
if(Integer.MAX_VALUE/10 < res || (Integer.MAX_VALUE/10 == res && Integer.MAX_VALUE%10 < cur)) {
return posi ? Integer.MAX_VALUE : Integer.MIN_VALUE;
}
res = res * 10 + cur;
}
return posi ? res : -res;
}
}
本文介绍了一个将字符串转换为整数(atoi)的方法,并提供了一个详细的Java代码示例。通过对输入字符串进行预处理、符号判断及数值转换,确保了转换过程的准确性。
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