#include<iostream>
#include<vector>
#include<algorithm>
#include<cstdio>
#include<queue>
#include<stack>
#include<string>
#include<map>
#include<set>
#include<cmath>
#include<cassert>
#include<cstring>
#include<iomanip>
using namespace std;
#ifdef _WIN32
#define i64 __int64
#define out64 "%I64d\n"
#define in64 "%I64d"
#else
#define i64 long long
#define out64 "%lld\n"
#define in64 "%lld"
#endif
#define FOR(i,a,b) for( int i = (a) ; i <= (b) ; i ++)
#define FF(i,a) for( int i = 0 ; i < (a) ; i ++)
#define FFD(i,a) for( int i = (a)-1 ; i >= 0 ; i --)
#define S64(a) scanf(in64,&a)
#define SS(a) scanf("%d",&a)
#define LL(a) ((a)<<1)
#define RR(a) (((a)<<1)+1)
#define SZ(a) ((int)a.size())
#define PP(n,m,a) puts("---");FF(i,n){FF(j,m)cout << a[i][j] << ' ';puts("");}
#define pb push_back
#define CL(Q) while(!Q.empty())Q.pop()
#define MM(name,what) memset(name,what,sizeof(name))
#define read freopen("in.txt","r",stdin)
#define write freopen("out.txt","w",stdout)
const int inf = 0x3f3f3f3f;
const i64 inf64 = 0x3f3f3f3f3f3f3f3fLL;
const double oo = 10e9;
const double eps = 10e-10;
const double pi = acos(-1.0);
i64 gcd(i64 _a, i64 _b)
{
if (!_a || !_b)
{
return max(_a, _b);
}
i64 _t;
while (_t = _a % _b)
{
_a = _b;
_b = _t;
}
return _b;
};
i64 ext_gcd (i64 _a, i64 _b, i64 &_x, i64 &_y)
{
if (!_b)
{
_x = 1;
_y = 0;
return _a;
}
i64 _d = ext_gcd (_b, _a % _b, _x, _y);
i64 _t = _x;
_x = _y;
_y = _t - _a / _b * _y;
return _d;
}
i64 invmod (i64 _a, i64 _p)
{
i64 _ans, _y;
ext_gcd (_a, _p, _ans, _y);
_ans < 0 ? _ans += _p : 0;
return _ans;
}
string s;
bool low(char x)
{
if(x<='z' && x>='a')
{
return true;
}
return false;
}
bool up(char x)
{
if(x<='Z' && x>='A')
{
return true;
}
return false;
}
const int maxn = 10111;
int dp[maxn];
int d2[maxn];
int ans;
int main()
{
int temp=0;
int t2=0;
ans = inf;
cin>>s;
dp[0]=0;
for(int i=0;i<s.length();i++)
{
if(low(s[i]))
{
temp++;
}
dp[i+1] = temp;
}
d2[s.length()]=0;
for(int i=s.length()-1;i>=0;i--)
{
if(up(s[i]))
{
t2++;
}
d2[i] = t2;
}
for(int i=0;i<=s.length();i++)
{
ans = min(ans,dp[i]+d2[i]);
}
cout<<ans<<endl;
// system("pause");
return 0;
}
Codeforces Round #116 (Div. 2, ACM-ICPC Rules) C - Letter
最新推荐文章于 2020-04-03 19:47:17 发布