Rob Kolstad
Palindromes are numbers that read the same forwards as backwards. The number 12321 is a typical palindrome.
Given a number base B (2 <= B <= 20 base 10), print all the integers N (1 <= N <= 300 base 10) such that the square of N is palindromic when expressed in base B; also print the value of that palindromic square. Use the letters 'A', 'B', and so on to represent the digits 10, 11, and so on.
Print both the number and its square in base B.
PROGRAM NAME: palsquare
INPUT FORMAT
A single line with B, the base (specified in base 10).SAMPLE INPUT (file palsquare.in)
10
OUTPUT FORMAT
Lines with two integers represented in base B. The first integer is the number whose square is palindromic; the second integer is the square itself.SAMPLE OUTPUT (file palsquare.out)
1 1 2 4 3 9 11 121 22 484 26 676 101 10201 111 12321 121 14641 202 40804 212 44944 264 69696
/*
ID:qhn9992
PROG:palsquare
LANG:C++
*/
#include <iostream>
#include <cstdio>
#include <cstring>
#include <string>
using namespace std;
int base;
char str[1000],show[1000];
char idx(int x)
{
if(x>=0&&x<=9) return x+'0';
else return x-10+'A';
}
void change(int x)
{
int e=base,cnt=0;
while(x)
{
int t=x%e;
x/=e;
str[cnt++]=idx(t);
}
str[cnt]=0;
}
void Show(int x)
{
int e=base,cnt=0;
while(x)
{
int t=x%e;
x/=e;
show[cnt++]=idx(t);
}
show[cnt]=0;
for(int i=0,j=cnt-1;i<j;i++,j--)
{
swap(show[i],show[j]);
}
}
bool ck()
{
int t=strlen(str);
for(int i=0,j=t-1;i<j;j--,i++)
{
if(str[i]!=str[j]) return false;
}
return true;
}
int main()
{
freopen("palsquare.in","r",stdin);
freopen("palsquare.out","w",stdout);
cin>>base;
for(int i=1;i<=300;i++)
{
change(i*i);
if(ck())
{
Show(i);
cout<<show<<" "<<str<<endl;
}
}
return 0;
}
本文深入探讨了在不同基数下找到回文数的平方,并以该基数表示回文平方数的过程。通过代码实现,展示了如何在指定范围内生成这样的数对,为数学爱好者提供了独特的解题思路。
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