要注意的是队列里入队条件有些变化
#include<stdio.h> #include<queue> #include<string.h> #include<stdlib.h> #include<math.h> using namespace std; int n,m,sx,sy,ex,ey; char map[210][210]; int mini[210][210]; int h[4]={1,-1,0,0}; int g[4]={0,0,1,-1}; struct point{ int x; int y; int time; }; void bfs(){ struct point cur; cur.x=sx; cur.y=sy; cur.time=0; queue<struct point> que; que.push(cur); while(!que.empty()){ struct point tem; tem=que.front(); que.pop(); for(int i=0;i<4;i++){ int xx=tem.x+h[i]; int yy=tem.y+g[i]; if(xx<0 || xx>=n || yy<0 || yy>=m) continue; if(map[xx][yy]=='#') continue; if(map[xx][yy]=='a'){ if(tem.time+1<mini[xx][yy]) mini[xx][yy]=tem.time+1; } else if(map[xx][yy]=='.'){ if(tem.time+1<mini[xx][yy]){ mini[xx][yy]=tem.time+1; struct point pp; pp.x=xx;pp.y=yy;pp.time=tem.time+1; que.push(pp); } } else if(map[xx][yy]=='x'){ if(tem.time+2<mini[xx][yy]){ mini[xx][yy]=tem.time+2; struct point pp; pp.x=xx;pp.y=yy;pp.time=tem.time+2; que.push(pp); } } } } } int main(){ int i,j; while(scanf("%d %d",&n,&m)!=EOF){ for(i=0;i<n;i++) scanf("%s",map[i]); for(i=0;i<n;i++) for(j=0;j<m;j++){ if(map[i][j]=='r'){ sx=i; sy=j; } else if(map[i][j]=='a'){ ex=i; ey=j; } mini[i][j]=1000000; } mini[sx][sy]=0; bfs(); if(mini[ex][ey]==1000000){ printf("Poor ANGEL has to stay in the prison all his life.\n"); } else printf("%d\n",mini[ex][ey]); } return 0; }ZOJ 1649 Rescue BFS水题
最新推荐文章于 2019-08-09 20:14:37 发布
