1. 树查询 Java代码 create table tree ( id number(10) not null primary key, name varchar2(100) not null, super number(10) not null // 0 is root ); -- 从子到父 select * from tree start with id = ? connect by id = prior super -- 从父到子 select * from tree start with id = ? connect by prior id = suepr -- 整棵树 select * from tree start with super = 0 connect by prior id = suepr
2. 分页查询 Java代码 select * from ( select my_table.*, rownum my_rownum from ( select name, birthday from employee order by birthday ) my_table where rownum < 120 ) where my_rownum >= 100;
3. 累加查询, 以scott.emp为例 Java代码 select empno, ename, sal, sum(sal) over(order by empno) result from emp;
EMPNO ENAME SAL RESULT ---------- ---------- ---------- ---------- 7369 SMITH 800 800 7499 ALLEN 1600 2400 7521 WARD 1250 3650 7566 JONES 2975 6625 7654 MARTIN 1250 7875 7698 BLAKE 2850 10725 7782 CLARK 2450 13175 7788 SCOTT 3000 16175 7839 KING 5000 21175 7844 TURNER 1500 22675 7876 ADAMS 1100 23775 7900 JAMES 950 24725 7902 FORD 3000 27725 7934 MILLER 1300 29025
4. 高级group by
Java代码 select decode(grouping(deptno),1,'all deptno',deptno) deptno, decode(grouping(job),1,'all job',job) job, sum(sal) sal from emp group by ROLLUP(deptno,job); DEPTNO JOB SAL ---------------------------------------- --------- ---------- 10 CLERK 1300 10 MANAGER 2450 10 PRESIDENT 5000 10 all job 8750 20 CLERK 1900 20 ANALYST 6000 20 MANAGER 2975 20 all job 10875 30 CLERK 950 30 MANAGER 2850 30 SALESMAN 5600 30 all job 9400 all deptno all job 29025
5. use hint 当多表连接很慢时,用ORDERED提示试试,也许会快很多 Java代码 SELECT /**//*+ ORDERED */* FROM a, b, c, d WHERE