杭电OJ——1228 A+B

A + B

Problem Description

读入两个小于100的正整数A和B,计算A+B.
需要注意的是:A和B的每一位数字由对应的英文单词给出.

Input

测试输入包含若干测试用例,每个测试用例占一行,格式为"A + B =",相邻两字符串有一个空格间隔.当A和B同时为0时输入结束,相应的结果不要输出.

Output

对每个测试用例输出1行,即A+B的值.

Sample Input

one + two = three four + five six = zero seven + eight nine = zero + zero =

Sample Output

3 90 96

Source

浙大计算机研究生复试上机考试-2005年

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JGShining

代码如下：

#include<stdio.h>
#include<stdlib.h>
#include<string.h>
int covert(char s[])
{ 
 if(!strcmp(s,"zero")) return 0;
 else if(!strcmp(s,"one")) return 1;
 else if(!strcmp(s,"two")) return 2;
 else if(!strcmp(s,"three")) return 3;
 else if(!strcmp(s,"four")) return 4;
 else if(!strcmp(s,"five")) return 5;
 else if(!strcmp(s,"six")) return 6;
 else if(!strcmp(s,"seven")) return 7;
 else if(!strcmp(s,"eight")) return 8;
 else if(!strcmp(s,"nine")) return 9;
 return 0;
}
int main()
{
 int a,b;
 char s[6];
 while(1)
 {
  for(a=0,scanf("%s",s);s[0]!='+';scanf("%s",s))
   a=a*10+covert(s);
  for(b=0,scanf("%s",s);s[0]!='=';scanf("%s",s))
   b=b*10+covert(s);
  if(a+b==0) return 0;
  printf("%d\n",a+b);
 }
 system("pause");
 return 0;
}