杭电OJ——1196 Lowest Bit(水题)

Lowest Bit


Problem Description
Given an positive integer A (1 <= A <= 100), output the lowest bit of A.

For example, given A = 26, we can write A in binary form as 11010, so the lowest bit of A is 10, so the output should be 2.

Another example goes like this: given A = 88, we can write A in binary form as 1011000, so the lowest bit of A is 1000, so the output should be 8.

Input
Each line of input contains only an integer A (1 <= A <= 100). A line containing "0" indicates the end of input, and this line is not a part of the input data.

Output
For each A in the input, output a line containing only its lowest bit.

Sample Input

 
26 88 0

Sample Output

 
2 8

Author
SHI, Xiaohan

Source

Recommend
Ignatius.L
大水题!很简单!直接发代码!
#include<iostream>
using namespace std;

int main()
{
	int num,sum,i,j,temp;
	while(cin>>num && num!=0)
	{
	   sum=1;temp=0;
       for(i=1;temp==0;i++)
	   {
		   temp=num%2;
		   //arr[i]=num%2;
		   num=num/2;
	   }
	   //cout<<"i="<<i<<endl;
	   //for(;;i--)
		   //if(arr[i]==1)
			   //break;
	   for(j=1;j<i-1;j++)
		   sum=sum*2;
	   cout<<sum<<endl;
	}
	return 0;
}


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