Given an array of integers, find two numbers such that they add up to a specific target number.
The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2. Please note that your returned answers (both index1 and index2) are not zero-based.
You may assume that each input would have exactly one solution.
Input: numbers={2, 7, 11, 15}, target=9
Output: index1=1, index2=2
The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2. Please note that your returned answers (both index1 and index2) are not zero-based.
You may assume that each input would have exactly one solution.
Input: numbers={2, 7, 11, 15}, target=9
Output: index1=1, index2=2
public class Solution {
public int[] twoSum(int[] nums, int target) {
int[] result = {-1, -1};
if (nums == null || nums.length <= 1)
return result;
HashMap<Integer, Integer> map = new HashMap<Integer, Integer>();
map.put(nums[0], 0);
for (int i = 1; i < nums.length; i++) {
if (map.containsKey(target - nums[i])) {
result[0] = map.get(target - nums[i]) + 1;
result[1] = i + 1;
break;
}
map.put(nums[i], i);
}
return result;
}
}
本文介绍了一个算法,用于在给定数组中找到两个元素,它们的和等于指定的目标数。该算法返回这两个元素的索引,且确保索引1小于索引2。每个输入都有唯一解。
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