Given an array of integers, find two numbers such that they add up to a specific target number.
The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2. Please note that your returned answers (both index1 and index2) are not zero-based.
You may assume that each input would have exactly one solution.
Input: numbers={2, 7, 11, 15}, target=9
Output: index1=1, index2=2
Code:
<span style="font-size:14px;">class Solution {
public:
vector<int> twoSum(vector<int> &numbers, int target) {
vector<int> result;
unordered_map<int, int> hashTable;
const int length = numbers.size();
for (int i = 0; i < length; ++i) {
if (hashTable.find(target-numbers[i]) != hashTable.end()) {
result.push_back(hashTable[target-numbers[i]]);
result.push_back(i+1);
return result;
} else
hashTable[numbers[i]] = i+1;
}
return result;
}
};</span>

本文介绍了一个算法,用于在整数数组中找到两个数,它们相加等于指定的目标值。通过使用哈希表,该算法可以在一次遍历数组的情况下高效地找到答案。
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