Leetcode - Reversed Linked ListII

iteye_17352

于 2015-05-19 22:19:01 发布

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分类专栏： List 文章标签： java

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本文介绍了一个Java方法，用于在给定范围内反转链表的一部分。该方法接收链表头节点及两个整数作为参数，实现原地反转指定区间的链表，并提供了一次遍历的高效解决方案。

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Reverse a linked list from position m to n. Do it in-place and in one-pass.

For example:
Given 1->2->3->4->5->NULL, m = 2 and n = 4,

return 1->4->3->2->5->NULL.

Note:
Given m, n satisfy the following condition:
1 ≤ m ≤ n ≤ length of list.

public ListNode reverseBetween(ListNode head, int m, int n) {
        // Start typing your Java solution below
        // DO NOT write main() function
        if(m == n)
            return head;
            
        ListNode pBefore = new ListNode(-1);
        pBefore.next = head;
        ListNode prev, curr = head,next;
        
        int c = 1;
        while(c < m){
            pBefore = pBefore.next;
            c++;
        }
        
        ListNode mNode = pBefore.next;
        prev = pBefore.next;
        curr = prev.next;
        while(c < n){
            next = curr.next;
            curr.next = prev;
            prev = curr;
            curr = next;
            c++;
        }
        pBefore.next = prev;
        mNode.next = curr;
        
        return mNode == head ? pBefore.next : head;
    }