Answer to Best of Ruby Quiz quiz 03

最新推荐文章于 2025-07-24 17:34:18 发布

原创最新推荐文章于 2025-07-24 17:34:18 发布 · 123 阅读

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#Ruby #XML

本文介绍了一个使用Ruby编写的简单GEDCOM解析器实现过程。该解析器通过解析GEDCOM文件来构建XML文档，适用于家谱数据的读取与转换。代码中详细展示了如何逐行读取GEDCOM文件，并将其转换为XML格式。

Answer to "GEDCOM Parser" version 1

require "rexml/document"
include REXML


Global_pattern = /\S+/
Id_pattern = /\@(.*)\@/
Tag_pattern = /[A-Z]{3,4}/
doc = node = Document.new
previous_level = -1

def convert_to_node(doc, line)
  cool = line.scan(Global_pattern)
  if cool[1].match(Tag_pattern)
    node = doc.add_element(cool[1])
    node.text = cool[2..-1].join(" ")
  elsif cool[1].match(Id_pattern)
    if cool[2].match(Tag_pattern)
      node = doc.add_element(cool[2])
      node.add_attribute("id", cool[1])
    else
      exit
    end
  else
    exit
  end
end

file = File.open("hello03")
#root = node.add_element("ok" + file.gets()[0].chr)
convert_to_node(node, file.gets())
file.each do |line|
  line_num = line[0].chr.to_i
  if previous_level < line_num
    if line_num - previous_level == 2
      node = node.elements[node.elements.size]
#      node.add_element("ok" + line_num.to_s)
      convert_to_node(node, line)
      previous_level += 1
    elsif line_num - previous_level == 1
#      node.add_element("ok" + line_num.to_s)
    convert_to_node(node, line)
    end
  else
    (previous_level - line_num + 1).times do
      node = node.parent
    end
    previous_level = line_num - 1
#    node.add_element("ok" + line_num.to_s)
    convert_to_node(node, line)
  end
end


File.open("cool005.xml","w") do |file|
  doc.elements.each do |line|
    file.puts line

  end
end