hibernate 基本事务

业务需求：增加一个人，这个人有两个地址，人是一张表，两个地址是一张表。一个人，两个地址全部保存是一个事务，否则谁也不保存。

1，Person类：

package com.supan.bean;
import java.util.HashSet;
import java.util.List;
import java.util.Set;
public class Person {
	private int id;
	private String name;
	private int age;
    private Set<Address> addresss = new HashSet<Address>();
	public int getId() {
		return id;
	}
	public void setId(int id) {
		this.id = id;
	}
	public String getName() {
		return name;
	}
	public void setName(String name) {
		this.name = name;
	}
	public int getAge() {
		return age;
	}
	public void setAge(int age) {
		this.age = age;
	}
	public Set<Address> getAddresss() {
		return addresss;
	}
	public void setAddresss(Set<Address> addresss) {
		this.addresss = addresss;
	}
}

Person的映射文件：

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE hibernate-mapping PUBLIC
        "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
        "http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<hibernate-mapping default-lazy="true" default-access="property" package="com.supan.bean" >
    <class name="Person" dynamic-update="true" dynamic-insert="true" table="myperson">
        <id name="id" column="id" type="integer">
            <generator class="native"/>
        </id>
        <property name="name" type="string" column="name" length="20"/>
        <property name="age" type="integer" column="age" length="3"/>
        <set name="addresss" inverse="true" cascade="all" >
             <key column="personid"/>
             <one-to-many class="Address"/>
        </set>
    </class>
</hibernate-mapping>

2，Address类

package com.supan.bean;
public class Address {
	private int id;
	private String name;
	private String info;
    private String remark;
    private Person person;
	public Person getPerson() {
		return person;
	}
	public void setPerson(Person person) {
		this.person = person;
	}
	public int getId() {
		return id;
	}
	public void setId(int id) {
		this.id = id;
	}
	public String getName() {
		return name;
	}
	public void setName(String name) {
		this.name = name;
	}
	public String getInfo() {
		return info;
	}
	public void setInfo(String info) {
		this.info = info;
	}
	public String getRemark() {
		return remark;
	}
	public void setRemark(String remark) {
		this.remark = remark;
	}
}

Address映射文件：

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE hibernate-mapping PUBLIC
        "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
        "http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<hibernate-mapping default-lazy="true" default-access="property" package="com.supan.bean" >
    <class name="Address" dynamic-update="true" dynamic-insert="true" table="address">
        <id name="id" column="id" type="integer">
            <generator class="native"/>
        </id>
        <property name="name" type="string" column="NAME" length="20"/>
        <property name="info" type="string" column="INFO" length="30"/>
        <property name="remark" type="string" column="REMARK" length="30"/>
        <many-to-one name="person" class="Person" column="personid" not-null="true"></many-to-one>
    </class>
</hibernate-mapping>

3，测试类：

	/**
	 * 该测试类，结果是，人，和两个地址都保存不成功，事务回滚
	 */
	public void testInsert() {
		Configuration config = new Configuration().configure();
		SessionFactory sf = config.buildSessionFactory();
		Session sess = sf.openSession();
		Transaction tx = null;
		try {
			sess = sf.openSession();
			tx = sess.beginTransaction();// 相当于JDBC的connection.setAutoCommit(false);

			Person person = new Person();
			person.setName("陈超阳");
			person.setAge(27);
			//先保存人，这个人是一定能保存成功的。
			sess.save(person);
			System.out.println("人已经保存到数据库中");

			Address address = new Address();
			address.setName("aaaaa");
			address.setInfo("aaaaa");
			address.setRemark("aaaaa");
			//保存第一个地址，这个地址是保存不成功的，因为personid不能为null
			//该句会抛出一个异常
			sess.persist(address);

			Address address2 = new Address();
			address2.setName("bbbbbbbbbb");
			address2.setInfo("bbbbbbbbbbb");
			address2.setRemark("bbbbbbbbbb");
			sess.persist(address2);

			tx.commit();// 
		} catch (HibernateException e) {
			if (tx != null)
				tx.rollback();// 相当于JDBC的connection.rollback();
			throw e;
		} finally {
			if (sess != null)
				sess.close();
		}
	}