http://poj.org/problem?id=2485
由于本题是多CASE,全局变量忘记重置了,唉,WA了好多次!!!
Highways
| Time Limit:1000MS | Memory Limit:65536K |
Description
The island nation of Flatopia is perfectly flat. Unfortunately, Flatopia has no public highways. So the traffic is difficult in Flatopia. The Flatopian government is aware of this problem. They're planning to build some highways so that it will be possible to drive between any pair of towns without leaving the highway system.
Flatopian towns are numbered from 1 to N. Each highway connects exactly two towns. All highways follow straight lines. All highways can be used in both directions. Highways can freely cross each other, but a driver can only switch between highways at a town that is located at the end of both highways.
The Flatopian government wants to minimize the length of the longest highway to be built. However, they want to guarantee that every town is highway-reachable from every other town.
Flatopian towns are numbered from 1 to N. Each highway connects exactly two towns. All highways follow straight lines. All highways can be used in both directions. Highways can freely cross each other, but a driver can only switch between highways at a town that is located at the end of both highways.
The Flatopian government wants to minimize the length of the longest highway to be built. However, they want to guarantee that every town is highway-reachable from every other town.
Input
The first line of input is an integer T, which tells how many test cases followed.
The first line of each case is an integer N (3 <= N <= 500), which is the number of villages. Then come N lines, the i-th of which contains N integers, and the j-th of these N integers is the distance (the distance should be an integer within [1, 65536]) between village i and village j. There is an empty line after each test case.
The first line of each case is an integer N (3 <= N <= 500), which is the number of villages. Then come N lines, the i-th of which contains N integers, and the j-th of these N integers is the distance (the distance should be an integer within [1, 65536]) between village i and village j. There is an empty line after each test case.
Output
For each test case, you should output a line contains an integer, which is the length of the longest road to be built such that all the villages are connected, and this value is minimum.
Sample Input
1 3 0 990 692 990 0 179 692 179 0
Sample Output
692
/* Author : yan
* Question : POJ 2485 Highways
* Date && Time : Wednesday, February 16 2011 04:28 PM
* Compiler : gcc (Ubuntu 4.4.3-4ubuntu5) 4.4.3
*/
#include<stdio.h>
#define MAX 501
int map[MAX][MAX];
int father[MAX];
int rank[MAX];
typedef struct _route
{
int x,y;
int weight;
}Route;
Route route[MAX*MAX/2];
int route_cnt;
int ans;
void initial()
{
ans=-1;
route_cnt=0;
unsigned int i;
memset(rank,0,sizeof(rank));
for(i=0;i<MAX;i++) father[i]=i;
}
int Find_Set(int x)
{
if(x!=father[x]) father[x]=Find_Set(father[x]);
return father[x];
}
int Union_Set(int x,int y,int w)
{
int a=Find_Set(x);
int b=Find_Set(y);
if(a==b) return 0;
if(rank[x]<rank[y])
{
father[a]=b;
}
else
{
father[b]=a;
if(rank[x]==rank[y]) rank[x]++;
}
ans=ans>w?ans:w;
return 1;
}
int cmp(const void *a,const void *b)
{
return (*(Route *)a).weight - (*(Route *)b).weight;
}
int main()
{
//freopen("input","r",stdin);
unsigned int n,i,j,test;
scanf("%d",&test);
while(test--)
{
initial();
scanf("%d",&n);
for(i=0;i<n;i++)
{
for(j=0;j<n;j++) scanf("%d",&map[i][j]);
}
for(i=0;i<n;i++)
{
for(j=i+1;j<n;j++)
{
route[route_cnt].x=i;
route[route_cnt].y=j;
route[route_cnt].weight=map[i][j];
route_cnt++;
}
}
qsort(route,route_cnt,sizeof(route[0]),cmp);
for(i=0;i<route_cnt;i++)
{
Union_Set(route[i].x,route[i].y,route[i].weight);
//printf("%d %d %d/n",route[i].x,route[i].y,route[i].weight);
}
printf("%d/n",ans);
}
return 0;
}
本文通过解决POJ2485高速公路问题,介绍了如何利用最小生成树算法找到连接所有节点且最长边最短的解决方案。文章详细展示了从输入处理到实现Kruskal算法的具体步骤。
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