http://poj.org/problem?id=2407
Relatives
| Time Limit:1000MS | Memory Limit:65536K | |
| Total Submissions:6610 | Accepted:2992 |
Description
Given n, a positive integer, how many positive integers less than n are relatively prime to n? Two integers a and b are relatively prime if there are no integers x > 1, y > 0, z > 0 such that a = xy and b = xz.
Input
There are several test cases. For each test case, standard input contains a line with n <= 1,000,000,000. A line containing 0 follows the last case.
Output
For each test case there should be single line of output answering the question posed above.
Sample Input
7 12 0
Sample Output
6 4
在数论,对正整数n,欧拉函数是少于或等于n的数中与n互质的数的数目。此函数以其首名研究者欧拉命名,
它又称为Euler's totient function、φ函数、欧拉商数等。 例如φ(8)=4,因为1,3,5,7均和8互质。
从欧拉函数引伸出来在环论方面的事实和拉格朗日定理构成了欧拉定理的证明。
/* Author : yan
* Question : POJ 2407 Relatives
* Date && Time : Saturday, January 29 2011 02:11 PM
* Compiler : gcc (Ubuntu 4.4.3-4ubuntu5) 4.4.3
*/
#include<stdio.h>
unsigned euler(unsigned x)
{// 就是公式
unsigned i, res=x,tmp;
tmp= (int)sqrt(x * 1.0) + 1;
for (i = 2; i <tmp; i++)
if(x%i==0)
{
res = res / i * (i - 1);
while (x % i == 0) x /= i; // 保证i一定是素数
}
if (x > 1) res = res / x * (x - 1);
return res;
}
int main()
{
//freopen("input","r",stdin);
int in;
while(scanf("%d",&in) && in)
{
printf("%d/n",euler(in));
}
return 0;
}
本文解析了POJ2407题目“Relatives”,介绍了使用欧拉函数解决该问题的方法。通过计算小于给定正整数n且与n互质的数的数量,实现了对问题的有效解答。
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