A + B
Time Limit: 2000/1000 MS (Java/Others)Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 10502Accepted Submission(s): 6043
Total Submission(s): 10502Accepted Submission(s): 6043
Problem Description
读入两个小于100的正整数A和B,计算A+B.
需要注意的是:A和B的每一位数字由对应的英文单词给出.
需要注意的是:A和B的每一位数字由对应的英文单词给出.
Input
测试输入包含若干测试用例,每个测试用例占一行,格式为"A + B =",相邻两字符串有一个空格间隔.当A和B同时为0时输入结束,相应的结果不要输出.
Output
对每个测试用例输出1行,即A+B的值.
Sample Input
one + two = three four + five six = zero seven + eight nine = zero + zero =
Sample Output
3 90 96
#include <iostream>
#include <map>
#include <string>
using namespace std;
map<string,int> Map;
void init()
{
Map["one"]=1;//注意这个操作必须放在函数内,自定义函数或main函数。函数体外只能声明定义基本类型,及常量。
Map["two"]=2;
Map["three"]=3;
Map["four"]=4;
Map["five"]=5;
Map["six"]=6;
Map["seven"]=7;
Map["eight"]=8;
Map["nine"]=9;
Map["zero"]=0;
}
int main()
{
init();
while(1)
{
string s;
int a=0;
while(cin>>s&&s!="+")
{
a=a*10+Map[s];
}
int b=0;
while(cin>>s&&s!="=")
{
b=b*10+Map[s];
}
if(a==0&&b==0)
break;
cout<<a+b<<endl;
}
return 0;
}