[C/C++]_[初级]_[替换过滤utf8字符串里无效字符]

场景:

1. 分析数据时,获取到的数据是字符串,但是有可能不是正确的完整的utf8字符串,打印出来或输出到文件时表现出来的就是显示乱码.

这时候就需要过滤掉非法字符使utf8字符串能正确显示, 比如把非法字符替换为#

代码:

1. 这个函数的特性是1个个字符判断, 适合任意长度,任意构造的 utf8 (无效)字符串.

bool IREUtil::FilterUtf8(unsigned char * string,int length)
{
	if(!string)
	{
		return false;
	}
		
	unsigned char * bytes = string;
	unsigned char * end = bytes+length;

	
	//10xxxxxx 应该出现个数
	int count_s = 0;
	//10xxxxxx 剩余个数
	int minus_s = 0;
	while(bytes != end)
	{
		if(bytes[0] > 0xF7)
		{
			if(minus_s)
			{
				int m = count_s-minus_s+1;
				memset((void*)(bytes-m),'#',m);
			}
			minus_s = 0;
			count_s = 0;

			bytes[0] = '#';
			bytes+=1;
			continue;
		}

		if(bytes[0] <= 0x7F)
		{
			if(minus_s)
			{
				int m = count_