Description
ice_cream's world is a rich country, it has many fertile lands. Today, the queen of ice_cream wants award land to diligent ACMers. So there are some watchtowers are set up, and wall between watchtowers be build, in order to partition the ice_cream’s world. But how many ACMers at most can be awarded by the queen is a big problem. One wall-surrounded land must be given to only one ACMer and no walls are crossed, if you can help the queen solve this problem, you will be get a land.
Input
In the case, first two integers N, M (N<=1000, M<=10000) is represent the number of watchtower and the number of wall. The watchtower numbered from 0 to N-1. Next following M lines, every line contain two integers A, B mean between A and B has a wall(A and B are distinct). Terminate by end of file.
Output
Output the maximum number of ACMers who will be awarded.
One answer one line.
One answer one line.
Sample Input
8 10 0 1 1 2 1 3 2 4 3 4 0 5 5 6 6 7 3 6 4 7
Sample Output
3
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37#include<iostream> #include<cstdio> #include<cstring> using namespace std; int n,m; int f[1100]; int find(int x) { if(x==f[x]) return x; else { f[x]=find(f[x]); return f[x]; } } int main() { while(~scanf("%d%d",&n,&m)) { for(int i=0;i<n;i++) f[i]=i; int ans=0; int a,b; while(m--){ scanf("%d%d",&a,&b); int x=find(a); int y=find(b); if(x==y)//节点值相同,围成了一个环 ans++; else f[x]=y; } printf("%d\n",ans); } return 0; }