81. Search in Rotated Sorted Array II Leetcode Python

最新推荐文章于 2021-12-03 15:03:25 发布

原创最新推荐文章于 2021-12-03 15:03:25 发布 · 617 阅读

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本文探讨了含有重复元素的旋转有序数组搜索问题，并提供了两种解决思路：一是基于寻找枢轴并划分数组的方法；二是改进后的二分查找算法。通过具体实现展示了如何判断目标值是否存在。

Follow up for "Search in Rotated Sorted Array":
What if duplicates are allowed?

Would this affect the run-time complexity? How and why?

Write a function to determine if a given target is in the array.

generally we can have two methods to do this problem, the first one is based on finding pivot and then divide the array into two parts, then search.

second one is still based on Binary search.

class Solution:
    # @param A a list of integers
    # @param target an integer
    # @return a boolean
    def search(self, A, target):
        if len(A) == 0:
            return False
        low = 0
        high = len(A) - 1
        while low < high:
            mid = low + (high - low) / 2
            if A[mid] == target:
                return True
            if A[low] < A[mid]:
                if A[low] <= target < A[mid]:
                    high = mid - 1
                else:
                    low = mid + 1
            elif A[low] > A[mid]:
                if A[mid]< target <= A[high]:
                    low = mid +1
                else:
                    high = mid -1
            else:
                low += 1
        if A[low] == target:
            return True
        return False