HDU1093A+B for Input-Output Practice (V)(入门题C,Java两个版本)

本文介绍了一道典型的输入输出练习题“A+B”,包括题目描述、输入输出格式、样例及解答代码。使用C语言和Java实现,适用于初学者理解基本的输入输出操作。

摘要生成于 C知道 ,由 DeepSeek-R1 满血版支持, 前往体验 >

A+B for Input-Output Practice (V)

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 64946    Accepted Submission(s): 43409


Problem Description
Your task is to calculate the sum of some integers.
 

Input
Input contains an integer N in the first line, and then N lines follow. Each line starts with a integer M, and then M integers follow in the same line.
 

Output
For each group of input integers you should output their sum in one line, and with one line of output for each line in input.
 

Sample Input
  
2 4 1 2 3 4 5 1 2 3 4 5
 

Sample Output
  
10 15
 

Author
lcy


C语言AC代码:
#include <stdio.h>
int main()
{
    int n,m,x,sum;
    scanf("%d",&n);

        while(n--)
        {
            scanf("%d",&m);
            sum=0;
            while(m--)
            {
                scanf("%d",&x);
                sum+=x;
            }
            printf("%d\n",sum);
        }

    return 0;
}

Java AC代码:
public class Main {

	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);

		int n = sc.nextInt();
		while(n-->0){
			int m = sc.nextInt();
			int sum = 0;
			while(m-->0){
				int x = sc.nextInt();
				sum += x;
			}
			System.out.println(sum);
		}
	}

}



评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值